Amarketing executive is studying internet habits of married men and women during the 8am – 10pm time period on weekends ("prime internet time"). based on past data, he has determined that husbands are on the internet 10% of the time during prime internet time. it has also been determined that when the husband is on the internet during prime internet time, 40% of the time the wife is also on the internet. when the husband is not on the internet during prime internet time, the wife is on the internet 20% of the time. if the wife is on the internet during prime internet time, what is the probability that the husband is also on the internet?

Our required probability is 0.18.

Step-by-step explanation:

Since we have given that

Probability that husband is on the internet = 10% = 0.10

Probability that husband is not on the internet = 1-0.10 = 0.9

Probability that wife is on internet given that husband is on internet = 40% = 0.40

Probability that wife is on internet given that husband is not on internet = 20% = 0.20

Probability that wife is on internet is given by

So, Probability that the husband is also on internet given that wife is on internet is given by

Hence, our required probability is 0.18.

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.