Urn a contains 2 red and 4 white balls, and urn b contains 1 red and 1 white ball. a ball is randomly chosen from urn a and put into urn b, and a ball is then chosen from urn b. what is the conditional probability that the transferred ball was white given that a white ball is selected from urn b?

0.7991

Step-by-step explanation:

Given : Urn A contains 2 red and 4 white balls, and urn B contains 1 red and 1 white ball.

Let be the event that the transferred ball was white.

and be the event that the ball drawn from urn B was white.

Then by Bayes theorem, the conditional probability that the transferred ball was white given that a white ball is selected from urn B will be :-

Where,

[ by conditional probability formula]

[By law of total probability]

i.e.

Now,

Hence, the required probability =0.7991

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: