An automobile traveling at a rate of 30 ft/sec is approaching an intersection. when the automobile is 120 ft from the intersection, a truck traveling at the rate of 40 ft/sec crosses the intersection. the automobile and the truck are on roads that are at right angles to each other. how fast are the automobile and the truck seperating 2 sec after the truck leaves the intersection?

14ft/sec

Step-by-step explanation:

GIVEN:  An automobile traveling at a rate of 30 ft/sec is approaching an intersection. When the automobile is 120 ft from the intersection, a truck traveling at the rate of 40 ft/sec crosses the intersection.

IN SKETCH BELOW............. IN THE ATTACHMENT

A IS AUTOMOBILE AND V IS TRUCK AT TIME T= 0

TRUCK IS AT M AFTER T SECONDS...AUTOMOBILE IS AT L AFTER T SECS.

AT=120 '

After T seconds

AL= 30T

LV= 120-30T

VM= 40T

LM = ( let this be s)

now , ds/dt =

now in this equation put T=2 we get

ds/dt= 1400/100= 14 FPS

hence the two vehicles are separating at 14 ft/sec at T=2 seconds

c.

step-by-step explanation:

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)