If -1 is zero of polynomial p(x) =ax square -3(a-1)x-1 then find the value of a.

a = 1

Step-by-step explanation:

Since x = - 1 is a zero of p(x) then p(- 1) = 0

Substitute x = - 1 into p(x)

p(- 1) = a(- 1)² - 3(a - 1)(- 1) - 1 = 0, that is

a + 3(a - 1) - 1 = 0

a + 3a - 3 - 1 = 0

4a - 4 = 0 ( add 4 to both sides )

4a = 4 ( divide both sides by 4 )

a = 1

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.