Rewrite each expression as a sum or difference of terms. (i) (x+3)(x-3) (ii) (x^2-3)(x^2+3) (iii) (x^15+3)(x^15-3) (iv) (x-3)(x^2-9)(x+3) (v) (x^2+y^2)(x^2-y^2) (vi) (x^2+y^2)^2 (vii) (x-y)²(x+y)²
(viii) (x-y)²(x²+y²)² (x+y)²

All the answers are given below.

Step-by-step explanation:

(i) (x+3)(x-3) =x² -3² =x² -9 {Since (a+b)(a-b) =a² -b²}

(ii) (x²-3)(x²+3) =(x²)² -3² = {Since (a+b)(a-b) =a² -b²}

(iii)

(iv) (x-3)(x²-9)(x+3) =(x²-9)(x²-9)=(x²-9)²={Since, (a-b)² =a²-2ab+b²}

(v) (x²+y²)(x²-y²) = (x²)² -(y²)² =

(vi) (x²+y²)² ={Since (a+b)² =a²+2ab+b²}

(vii) (x-y)²(x+y)² =(x²-y²)² ={Since (a-b)² =a²-2ab+b² and (a+b)(a-b) =a²-b²}

(viii) (x-y)²(x²+y²)²(x+y)² =(x²+y²)²(x²-y²)² =(Answer)

3; 9 is 8 to -4

step-by-step explanation: