Write a polynomial function that meets the stated conditions. the zeros are −2 and 1.

A polynomial function that meet those conditions is x² + x - 2 = 0

Step-by-step explanation:

Hi there!

To solve this problem, let´s start writting a generic polynomial function in factored form. Since the function has two zeros, the factored form will have 2 terms:

(x+a)(x+b) = 0

For this equation to be 0, (x+a) or (x+b) have to be zero:

Then:

x + a = 0 ⇒ x = -a

In the same way:

x + b = 0 ⇒ x = -b

Then, the values "a" and "b" are equal to the zeros of the function but with the opposite sign.

In our case:

(x + a)(x + b) = 0

a = the zero of the function with opposite sign, that is, 2

b = -1

Then:

(x + 2)(x - 1) = 0

Apply distributive property:

x² - x + 2x - 2 = 0

x² + x - 2 = 0

Then, a polynomial function that meet those conditions is:

x² + x - 2 = 0

you would need to know all the numbers that are on there

step-by-step explanation:

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1