Use the method from the example to approximate the solution to the equations below to two decimal places.
6^x = 1,000

x = 3.85

Step-by-step explanation:

Given equation:

6ˣ = 1,000

now,

on taking log both sides, we get

⇒ log(6ˣ) = log(1,000)

or

⇒ log(6ˣ) = log(10³)

now we know the property of log function that

log(aᵇ) = b × log(a)

thus, applying the above property, we get

⇒ x × log(6) = 3log(10)

or

⇒ x × log(2×3) = 3log(10)

now,

we have another property of log function as":

log(A) = log(A) + log(B)

therefore,

x × [log(2) + log(3)] = 3log(10)

also,

log(10) = 1

log(2) = 0.3010

log(3) = 0.4771

Thus,

⇒ x × [0.3010 + 0.4771 ] = 3 × 1

or

⇒ x × 0.7781 = 3

or

⇒ x = 3.85

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

1st part is 64,000,000

2nd part 500,000

step-by-step explanation: