Let μ=e(x), σ=standard deviation of x. find the probability p(μ-σ ≤ x ≤ μ+σ) if x has a geometric distribution with p = 0.61. round your answer to 4 decimal places.

P(μ-σ ≤ X ≤ μ+σ) =

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

The standard deviation of the geometric distribution is given by the following formula:

In this problem, we have that:

.

So

P(μ-σ ≤ X ≤ μ+σ) =

P(μ-σ ≤ X ≤ μ+σ) =

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3