Consider the radical equation (3√6-x)+4=-8. explain why the calculation in problem 1 does not produce a solution to the equation.

See explanation below

Step-by-step explanation:

First we will solve the radical equation (which I guess was problem 1),

Let's start by simplifying it:

Now we will solve the equation by squaring both sides of the equation:

So the calculation for x was that x = -10

However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:

This happens because when we first squared both sides of the equation in the first part of the problem we missed one value for x (remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.

When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.

answer: x

step-by-step explanation:

the 3rd on is correct

step-by-step explanation: