Write an equation in point slope form of the line passes through the given point and has the given slope
(-6, -2); m = 3

y - 2 = 3( x - 6 )

Step-by-step explanation:

point slope form = y - y1 = M( x - x1 )

just plug in the numbers to get

y - 2 = 3( x - 6 )

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)