Suppose that 1010% of a certain batch of calculators have a defective case, and that 1414% have defective batteries. also, 55% have both a defective case and defective batteries. a calculator is selected from the batch at random. find the probability that the calculator has a good case and good batteries.

Our required probability is 81%.

Step-by-step explanation:

Since we have given that

Probability of defective calculators (C)= 10%

Probability of defective batteries (B) = 14%

Probability of both defective calculators and defective batteries = 5%

So, it becomes.

So, probability that the calculator has a good case and good batteries is given by

Hence, our required probability is 81%.

three-fourths of an hour

36÷48=0.75

0.75=

i think the length is 12 and the width is 17