The width of a rectangle is 6 m shorter than its length. if the perimeter of the rectangle is 52 m, find its length and width.

length = 16 m, width = 22 m

length = 29 m, width = 23 m

length = 29 m, width = 35 m

length = 16 m, width = 10 m

Length = 16 m , width = 10 m

Step-by-step explanation:

Let the Length of the rectangle be L meters.

Now, Width of the rectangle is (L-6) m.

Perimeter of the Rectangle = 52 m

Now, we know that

Perimeter of the Rectangle =  2(L+W)

⇒ 2(L+W) =  52 m

or, 2(L + (L-6)) = 52 m

Simplifying, we get 2L + 2L -12 = 52

or, 4L = 64

or, L = 16 m

So, width = L- 6 = (16-6) m = 10 m

So, length = 16 m

and width = 10 m

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step-by-step explanation:

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y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3