Mathematics, 23.10.2019 00:00 Will1119

Derive the equation of the parabola with a focus at (2, -1) and a directrix of y =
io
of(x) = -(x + 2)2 - 3
o 12%) = (x + 2% + 3
op(x) = -(x – 232 +
of(= = (x - 2)2 - 3

Answers: 1

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Derive the equation of the parabola with a focus at (2, -1) and a directrix of y =
io
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Derive the equation of the parabola with a focus at (2, -1) and a directrix of y = io of(x) = -(x + 2)2 - 3 o 12%) = (x + 2% + 3 op(x) = -(x – 232 + of(= = (x - 2)2 - 3

Answers

Another question on Mathematics

Derive the equation of the parabola with a focus at (2, -1) and a directrix of y =
io
of(x) = -(x + 2)2 - 3
o 12%) = (x + 2% + 3
op(x) = -(x – 232 +
of(= = (x - 2)2 - 3