East high school scored a total of 71 points in their final basketball game of the season. the team successfully made a total of 32 baskets. the score was composed of two-point baskets and three-point baskets.

the following system of equations can be used to model the number of two-point baskets, x, and the number of three-point baskets, y, that were made during the game.

first, determine the point on the graph that represents the solution to the system of equations. notice that one of the equations in the system has already been graphed.

then, determine the number of two-point baskets and three-point baskets that are made during the final basketball game of the season.

step-by-step explanation:

47 - 90 = 43

43 - 180 = x

x = 137

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

answer: im sorry i dont get it

step-by-step explanation: