Mathematics, 23.10.2019 22:00 tamaraquirozmorales

Consider a sampling distribution with p equals 0.12 and samples of size n each. using the appropriate formulas, find the mean and the standard deviation of the sampling distribution of the sample proportion.
(a) for a random sample of size n equals 5000.
(b) for a random sample of size n equals 1000.
(c) for a random sample of size n equals 500.

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Answer from: surfer89

Answer with explanation:

Consider a sampling distribution with p equals 0.12 and samples of size n each.

Then, formula for mean = p

Formula for standard deviation= $\sqrt{\dfrac{p(1-p)}{n}}$

(a) For a random sample of size n equals 5000.

Mean = 0.12

Standard deviation= $\sqrt{\dfrac{0.12(1-0.12)}{5000}}$

$\\\\0.00459565011723\approx0.0046$

(b) For a random sample of size n equals 1000.

Mean = 0.12

Standard deviation= $\sqrt{\dfrac{0.12(1-0.12)}{1000}}$

$\\\\=0.0102761860629\approx0.0103$

Mean = 0.12

Standard deviation= $\sqrt{\dfrac{0.12(1-0.12)}{500}}$

$\\\\=0.0145327216997\approx0.0145$

Answer from: Quest

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(continued on page 79)

step-by-step explanation:

Answer from: Quest

Ifound this on google “that means that the graph of a function with direct variation has these features: it is a straight line: because the slope is the ratio y/x = k. it passes through the origin (0,0): because y = kx = k (0) = 0.” i hope this you for what your looking for

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