Triangles abc and dbc have the following characteristics:

bc is a side of both triangles

∠acb and ∠dcb are right angles

ac ≅ dc

which congruence theorem can be used to prove △abc ≅ △dbc?

aas
sss
hl
sas

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

overpriced

step-by-step explanation:

35x 3= 105

step-by-step explanation:

35+35= 70   70 + 35= 105