Apsychologist set up an experiment to study the tendency of a person to select the first item when presented with a series of items. in the experiment, 300 people were presented with a set of five pictures arranged in random order. each person was asked to choose the most appealing picture. of the first 150 participants, 36 chose the first picture in the set. among the remaining 150 participants, p people chose the first picture in the set. if more than 20%of all participants chose the first picture in the set, which of the following inequalities best describes the possible values of p ?

a. p is greater than, 0.20 times, open parenthesis, 300 minus 36, close parenthesis, where p is less than or equal to 150
b. p is greater than, 0.20 times, open parenthesis, 300 plus 36, close parenthesis, where p is less than or equal to 150
c. p minus 36 is greater than, 0.20 times 300, where p is less than or equal to 150
d. p plus 36 is greater than, 0.20 times 300, where pis less than or equal to 150

Option D.

Step-by-step explanation:

First, let's do a little review of this excersice. Of the first 150 participants, 36 chose the first picture, and of the other 150 participants, p chose the first picture in the set.

Hence, the proportion of the participants who chose the first picture in the set is 36 300 p. Since more than 20% of all the participants chose the first picture, it follows that 36 0.20 300 !p . This inequality can be rewritten as p + 36 > 0.20(300). Since p is a number of people among the remaining 150 participants, p ≤ 150.  

Choices A, B, and C are incorrect and may be the result of some incorrect interpretations of the given information or of computational errors.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

the answer is 2/54

step-by-step explanation: