Ahare and a tortoise compete in a race over a course 1.50 km long. the tortoise crawls straight and steadily at its maximum speed of 0.290 m/s toward the finish line. the hare runs at its maximum speed of 7.55 m/s toward the goal for 1.200 km and then stops to tease the tortoise. how close to the goal can the hare let the tortoise approach before resuming the race, which the tortoise wins in a photo finish? assume that, when moving, both animals move steadily at their respective maximum speeds.

The answer is Th=39s and X= 11m

Step-by-step explanation:

The necessary time for the hare to complete the 0.290 km

Th=xf-xi/vh = 1500m-1200m÷7.55m/s=39s

then the tortoise must be  x distance from finish line so that the hare continues the race

x=vt

x= 0.290m/s(39s)=11,3m

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation:

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