−6x+14< −28 or 9x+15≤−12. solve for x

Solve for x:

−6x + 14 < −28 or 9x + 15 ≤ −12

1.

−6x + 14 < −28

Subtract 14 from both sides

-6x < -42

Divide both sides by -6. Flip the inequality since you're dividing by a negative.

x  > 7

2.

9x + 15 ≤ −12

Subtract 15 from both sides

9x ≤ -27

Divide both sides by 9

x ≤ -3

x  > 7 or x ≤ -3

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c