Find three consecutive intergers such that the sum of twice the smallest and 3 times the largest is 126

24

,

25

,

26

Step-by-step explanation:

Let's call the smallest integer  

n

. Then the next two consecutive integers are  

n

+

1

and  

n

+

2

.

"Sum of twice the smallest and 3 times the largest is 126"

2

(

n

)

+

3

(

n

+

2

)

=

126

2

n

+

3

n

+

6

=

126

5

n

+

6

=

126

5

n

=

120

n

=

24

So the smallest integer is  

24

.

The three consecutive integers are then:  

24

,  

25

, and  

26

.

investment b is an ordinary annuity with $3,909.64 in the account after one year.

step-by-step explanation: