18. let e = {u1, u2, u3} and f = {b1, b2}, where u1 = ⎧⎩ 1 0 −1 ⎫⎭ , u2 = ⎧⎩ 1 2 1 ⎫⎭ , u3 = ⎧⎩ −1 1 1 ⎫⎭ and b1 = (1,−1)t , b2 = (2,−1)t for each of the following linear transformations l from r3 into r2, find the matrix representing l with respect to the ordered bases e and f: (a) l (x) = (x3, x1)t (b) l (x) = (x1 + x2, x1 − x3)t (c) l (x) = (2x2,−x1)t

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.

-3(b-8)-5=9(b+2)+1

distribute

-3b+24-5=9b+18+1

add/ subtract

-3b+20=9b+19

20-19= 1

-3b+1=9b

9b+3b= 12b

1=12b

1 divided by 12 = 1/12

answer: 1/12 = b

answer: the answer to this problem is yes because 4n + 4 does equal 2m - 6

step-by-step explanation: first you have to calculate 2m - 6 second you have to calculate 4n + 4 finally you have to get your answer