Find the area under the standard normal probability distribution between the following pairs of z-scores. a. zequals0 and zequals1.00 e. zequalsminus1.00 and zequals0 b. zequals0 and zequals2.00 f. zequalsminus2.00 and zequals0 c. zequals0 and zequals3.00 g. zequalsnegative 1.49 and zequals0 d. zequals0 and zequals0.82 h. zequalsminus0.82 and zequals0

See below

Step-by-step explanation:

All this values can be easily found by using a table or a spreadsheet.

a)

P(0 ≤ z ≤ 1) = 0.3413

e)

P(-1 ≤ z ≤ 0) = P(0 ≤ z ≤ 1) = 0.3413 because N(0;1) is symmetrical

b)

P(0 ≤ z ≤ 2) = 0.4772

f)

P(-2 ≤ z ≤ 0) = P(0 ≤ z ≤ 2) = 0.4772

c)

P(0 ≤ z ≤ 3) = 0.4987

g)

P(-1.49 ≤ z ≤ 0) = 0.4319

d)

P(0 ≤ z ≤ 0.82) = 0.2939

h)

P(-0.82 ≤ z ≤ 0) = P(0 ≤ z ≤ 0.82) = 0.2939

it would be 3 ÷by 6 because the number on each side

think the answer is 30 degrees. if not than it is 20 degrees. not 100% sure. let me know if it was right.

gill russ