Ahigh-altitude spherical weather balloon expands as it rises, due to the drop in atmospheric pressure. suppose that the radius r increases at the rate of 0.02 inches per second, and that r = 36 inches at time t = 0. determine the equation that models the volume v of the balloon at time t, and find the volume when t = 360 seconds.

v(t) = 4π(0.02t)2; 651.44 in3

v(t) = 4π(36 + 0.02t)2; 1,694,397.14 in3

v(t) = four pi times the product of zero point zero two and t to the third power divided by three.; 4,690.37 in3

v(t) = four pi times the quantity of thirty six plus zero point zero two t to the third power divided by three.; 337,706.83 in3

V(t)=

337 706, 83

Step-by-step explanation:

The volume of a sphere is

So like the initial radius is 36 and is increasing of 0.02 every second, we define the radius:

r= 36+0.02t

So, we replace in the formula of the volume and we obtain

and if we replace t= 360 seconds in the equation of volume, we get

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step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

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