Five cards are drawn from a standard deck of cards.

a). how many groups of cards are possible?
b). how many groups would have 4 of a kind?

can you solve this in combinations (from probability unit, counting techniques) !

If all the cards are of the same suit, then since there are four suits in a deck, then the number is  4 x  13C4  = 4 x ( 13 x 12 x 11 x 10 ) / ( 4! )  = 2860.

If the cards are to be of different suits ,then the number of combinations would be

13 x 13  x 13 x 13 = 28561

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.