Over million tweets are sent per day (digital marketing ramblings website, december 15, 2014). assume that the number of tweets per hour follows a poisson distribution and that bob receives on average tweets during his lunch hour. a. what is the probability that bob receives no tweets during his lunch hour (to 4 decimals)? 0.0009 b. what is the probability that bob receives at least tweets during his lunch hour (to 4 decimals)? for this question, if calculating the probability manually make sure to carry at least 4 decimal digits in your calculations. 0.5169 c. what is the expected number of tweets bob receives during the first minutes of his lunch hour (to 1 decimal)? d. what is the probability that bob receives no tweets during the first minutes of his lunch hour (to 4 decimals)?

step-by-step explanation:

the first one

step-by-step explanation:

just id the test.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752