:
triangle def has coordinates d(2, 5); e(-1 5); f(1, 2). find the coordinates of the image d’e’f’ after a reflection across the y-axis. (2 points)

D' (-2,5), E' (1,5); and F' (-1,2)

Step by step explanation:

When one does a reflection across the y-axis, the values of the y-coordinate for the order pairs remain the same value, while the values of the x-coordinates flip their signs.

Therefore:

point D (2,5) becomes D' (-2,5)

point E (-1,5) becomes E' (1,5)

and point F (1,2) becomes F' (-1,2)

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step-by-step explanation:

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an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )