The volume of oil in a cylindrical container is increasing at a rate of 150 cubic inches per second. the height of the cylinder is approximately ten times the radius. at what rate is the height of the oil changing when the oil is 35 inches high?

Step-by-step explanation:

The volume of the cylindrical container is:

Where:

- Radius, in inches.

- Height, in inches.

The rate of change of the volume is:

The rate of change of the height is:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

answer4 to the second power is 16

and 4 to the third power is 64,