Suppose james randomly draws a card from a standard deck of 52 cards. he then places it back into the deck and draws a second card. a standard deck of cards contains four suits: clubs, diamonds, hearts, and spades. there are 13 cards in each suit, which includes three face cards: jack, queen, and king. what is the probability that james draws a queen card as the first card and a diamond card as the second card? express your answer as a percentage precise to two decimal places.

1.92%

Step-by-step explanation:

The probability for first case, picking a queen out of deck, will be:

as there will be 4 queens in a deck, one of each suit.

For the second pick, the probability of picking a diamond card, will be:

here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).

Thus the net probability for both cases will be:

Thus total probability for the combined two cases will be 1.92%

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.