Asequence of translations maps ∆abc to ∆a’b’c’.
∆abc has vertices a(-3, 4), b(-3, 0), c(-1, 3)
the coordinates for a’ are (3, -4)

(a) what is the coordinate rule that maps ∆abc onto ∆a’b’c’?

(b) what are the coordinates for b’ and c’?

(a) Co-ordinate rule is and

(b) Co-ordinates of B' and C' are and respectively.

Step-by-step explanation:

(a)

Here, the co-ordinates of A are translated to A'.

For the co-ordinates A and A',   and

So, x value of A has shifted to right by 6 units and y value of A has shifted 8 units down.

Hence, the co-ordinate rule that maps ΔABC onto ΔA'B'C' is:

and .

(b)

Using the co-ordinate rule, we can find the co-ordinates of B' and C'.

For B, and .

So, of B' is

And, of B' is .

Therefore, co-ordinates of B' are .

For C, and .

So, of C' is

And, of C' is .

Therefore, co-ordinates of C' are .

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

idk

step-by-step explanation:

use that smart brain