Sharon tried to solve an equation step by step.
\qquad\begin{aligned} 9& =-3(e-2) \\ 9& =-3e+6& \green{\text{step } 1} \\ 15& =3e& \blue{\text{step } 2} \\ 5& =e& \purple{\text{step } 3} \end{aligned}
9
9
15
5


=−3(e−2)
=−3e+6
=3e
=e


step 1
step 2
step 3


find sharon's mistake.

Figure abcde is a regular pentagon. segment ae is located at a (2, 1) and e (4, 1). what is the perimeter of abcde? 4 units 6 units 8 units 10 units

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.

The owner of the plant nursery where you were tells you to fill 350 ml bottles from a 30 l from a fertilizer