Astudent can solve 20 problems in 30 minutes. how long would it take him to solve 50 problems? (assume that the student works at the same pace).

Student takes 75 minutes to solve 50 problems.

SOLUTION:

Given that, a student can solve 20 problems in 30 minutes.  

We have to find the time to solve 50 problems. (Assume that the student works at the same pace).

Now, we know that,  

So, by cross multiplication method,

Cross multiplications steps: (To find Single Variable)

Step 1: Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.

Step 2: Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.

Step 3: Set the two products equal to each other.

Step 4: Solve for the variable.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet