Mathematics, 27.10.2019 05:43 amortegaa805
Evaluate 6t -20-32u6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u=
4
1
u, equals, start fraction, 1, divided by, 4, end fraction.
Answers: 1
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Evaluate 6t -20-32u6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u= <...
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