The sum of the ages of mr lee and his son is 53 now. 4 years ago, the age of mr lee was 4 times that of his son. find their ages now.

must be answered with an equation. any is appreciated : )

Now, Mr Lee's age is 40 years, his son's age is 13 years.

Step-by-step explanation:

4 years ago:

Son's age = x years

Mr. Lee age = 4x years

Now:

Son's age = x + 4 years

Mr. Lee age = 4x + 4 years

The sum of the ages of Mr Lee and his son is 53 now, so

Now, Mr Lee's age is 40 years, his son's age is 13 years.

Mr.Lee age = 40 years and his son age = 13 years

Explanation:

Let x & y be the ages of Mr.Lee and his son.

as per the question

x+y=53 ---------------------------------------- (1)eq.

4 years ago,

The relation given as per the problem (x-4)=4(y-4)

that implies x-4y= -12 -----------------------------(2) eq.

x=53-y from equation (1);

substitute x in equation - (2) ;

53-y-4y=-12;

53+12 = 5y ;

65=5y;

y+= 13 years;

x=53-13 = 40 years;

Therefore Mr.Lee age = 40 years and his son age = 13 years

repeat the question

step-by-step explanation:

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24