The length of a rectangle is four times it's width and has an area of 1024cm squared. work out the width of the rectangle

Width = 16 cm

Step-by-step explanation:

Given that

Area of rectangle = 1024 cm²

Length of rectangle = four times the width

Let the width of rectangle be  W cm

Now we know that Area of rectangle = Length × Width

Or,                          Area of rectangle = (4 × width ) × width

                                1024 cm² = 4 × W²

                                = W²

                                256 = W²

∴                               W =

Or,                            W = 16 cm

Hence the width of given rectangle is 16 cm        Answer.

the answer is 8/21

hope this

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)