Las cruces, nm, is about 600 mi from dallas, tx. one plane flies from
dallas to las cruces in 1 hr 12 min. and another plane with the same
air speed flies from las cruces to dallas in 1 hr 30 min. find the air
speed of the planes and the speed of the wind.

The air speed of the plane is 450 mph and that of the wind is 50 mph.

Step-by-step explanation:

Let the speed of the plane is u and that of wind is v.

Therefore, with (u + v) speed the plane goes from Dallas to Las Cruces, i.e. 600 miles in 1 hr and 12 minutes i.e. 1.2 hours.

So, .......... (1)

And with (u - v) speed the plane goes from Las Cruces to Dallas in 1 hour and 30 minutes i.e. 1.5 hours.

So, ......... (2)

Solving equation (1) and equation (2), we get 2u = 900, ⇒ u = 450 miles per hour.

Now, from equation (1), we get, v = 500 - 450 = 50 miles per hour.

So, the airspeed of the plane is 450 mph and that of the wind is 50 mph. (Answer)

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!