Complete the steps to factor 56x2 – 8x – 7x + 1 by grouping.

group pairs of terms with common factors.
(56x2 – 8x) + (–7x + 1)

factor the gcf from each group.
8x(7x – 1) –1(7x – 1)

use the distributive property.
what is the factorization of the polynomial?

(8x – 1)(7x – 1)
(8x + 1)(7x – 1)
(8x + 7x)(1 – 1)

(8x-1)(7x-1) The question leaves you with the partially factored equation: 8x(7x-1) - 1(7x-1) look at the partially factored equation, you'll see that both terms have (7x-1) as one of their factors. take that (7x-1) as a factor and divide both terms by (7x-1), giving you (8x(7x-1) - 1(7x-1)) / (7x-1) The (7x-1) factors cancel out, leaving you with (8x - 1) So your 2 factors are (7x-1) and (8x-1). Looking at the available options, the only correct one is (8x-1)(7x-1)

A:  (8x-1) (7x-1)

Step-by-step explanation:

got it right on edge

good luck on the assignment

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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