Suppose that 76% of americans prefer coke to pepsi. a sample of 200 was taken. what is the probability that at least sixty eight percent of the sample prefers coke to pepsi?

0.996

Step-by-step explanation:

It is given 76% of Americans prefer Coke to Pepsi.

A sample of 200 was taken,i.e n=200

Let X be the random variable denoting the number of Americans that prefer Coke to Pepsi.

Then X follows a Binomial Distribution with p=0.76

To find P(X>=136) [68% of 200 =136]

P(X>=136)=1-P(X<136) = 1-P(X<=135)

=1-0.003979

=0.996020

y/x=18

step-by-step explanation:

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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