−15x+4≤109 or −6x+70> −2minus, 15, x, plus, 4, is less than or equal to, 109, start color #ed5fa6, start text, space, o, r, space, end text, end color #ed5fa6, minus, 6, x, plus, 70, is greater than, minus, 2 choose 1 choose 1
(choice a) a x\geq-7x≥−7x, is greater than or equal to, minus, 7.
(choice b) b -7\leq x< 12−7≤x< 12minus, 7, is less than or equal to, x, is less than, 12.
(choice c) c x< 12x< 12x, is less than, 12.
(choice d) d there are no solutions .
(choice e) e all values of xxx are solutions.

Option E.

Step-by-step explanation:

The given inequalities are

We need to find the solution of given compound inequality.

Solve each inequality separately.

Solve first inequality:

Subtract 4 from both sides.

Divide both sides by -15. If we multiply or divide an inequality by a negative number, then the sign of inequality is changed.

             .... (1)

Solve second inequality:

Subtract 70 from both sides.

Divide both sides by -6.

                  .... (2)

Form (1) and (2) we get

Therefore, the correct option is E.

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step-by-step explanation:

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step-by-step explanation: