Asteel company is making flat rectangular frames as a part of a new product they are launching each frame will be cut out of a plece of steel

and will have a final area as close to 28 cm² as possible. the width of the frame needs to be uniform throughout. the inside dimensions of the

frame must be 11 cm by 6 cm.

complete the equation that models the above situation, and find the width of the frame, x

The problem has no real solution, because the area of inside of the frame is bigger than the total area of the frame.

Step-by-step explanation:

Any way here is the mathematical explanation/solve to this statement.

As show in the graphic, there is a representation of the situation stated in the problem. So in order to calculate the area we have the next equation as a function of x.

Area:

Solving the equation to find the roots (values of x):

So mathematically there is no real answer, since x is a width must be positive number. And practically the outer area must be bigger than the inner area, and the inner area is given by 6 times 11, or 66 .

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.