Bobs age is 4 times greater than susie's age. dakota is three years younger than susie. the sum of bob, susie, and dakota ages is 93. what is susies age

16 years

Step-by-step explanation:

Let

Bob's age be b

Susie's age be s

Dakota's age be d

Bob is 4 times than Susie, that means:

b = 4s

Dakota is 3 years YOUNGER than Susie, that means:

d = s - 3

Sum of all 3 is 93, that means:

b + s + d = 93

Putting 1st and 2nd equation in third, we can solve for Susie's age:

b + s + d = 93

4s + s + s - 3 = 93

6s - 3 = 93

6s = 93 + 3

6s = 96

s = 96/6

s = 16

Susie's age is 16 years

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1