3. a logo is designed as shown in the diagram below. a sector oab, of angle 60° and radius 20cm
is drawn. the perpendicular bd is dropped from b to oa and a quarter circle ead centered at d
is drawn. find the area of the shaded part, bae. bd is a perpendicular bisector of oda. area of
sector r20.
hint: subtract the sum of area of triangle and quarter circle from area of sector. :
2oum
e

step-by-step explanation:

i'm pretty sure it would take 20 hours because it's half the men so you multiply the number of hours it takes by 2

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true

i need a diagram

step-by-step explanation:

no

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: