Select the correct answer from each drop-down menu. for circle o, and m∠abc = 55°. in the figure, ∠ and ∠ have measures equal to 35°.

CA is a diameter of the circle, so m\widehat{AC}=180^\circmAC=180∘ , which means m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circm∠AOB=m∠AOD=mAD=180∘−mCD=55∘ . Then m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circm∠ABO=90∘−55∘=35∘ .

This means m\angle CBO=55^\circ-35^\circ=20^\circm∠CBO=55∘−35∘=20∘ . Also, if m\angle AOB=55^\circm∠AOB=55∘ , then m\angle BOC=180^\circ-55^\circ=125^\circm∠BOC=180∘−55∘=125∘ , which in turns tells us that m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circm∠BCO=180∘−20∘−125∘=35∘ .

plato

Step-by-step explanation:

The ratios

AD : DB

and

AE : EC

are equal.

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step-by-step explanation:

nndncnd cnn

snddnd