Rework problem 15 from the chapter 3 review section of your text, involving the selection of mice from a cage. assume that you have 11 mice in the cage: 3 white males, 5 gray females, and 3 gray males. two mice are selected simultaneously and at random, and their colors are noted. what is the probability that at least one mouse is female, given that exactly one is gray?

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

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x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

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step-by-step explanation:

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the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation:

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.