Alarge box contains 10,000 ball bearings. a random sample of 120 is chosen. the sample mean diameter is 10 mm, and the standard deviation is 0.24 mm. true or false: a. a 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 ± (1.96)(0.24)/√ 120. b. a 95% confidence interval for the mean diameter of the 10,000 bearings in the box is 10 ± (1.96)(0.24)/√120. c. a 95% confidence interval for the mean diameter of the 10,000 bearings in the box is 10 ± (1.96)(0.24)/√10,000.

Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is .

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 120

Sample mean = 10 mm

Standard Deviation = 0.24 mm

Formula:

Hence, the correct interpretation for the confidence interval is given by option a).

A 95% confidence interval for the mean diameter of the 120 bearings in the sample is .

We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00