If you have 2y-2x=3
-2y+5x= -9
how do you solve it using elimination method?

x=2, y=5 or (2,5)

Step-by-step explanation:

The elimination method is adding or subtracting two equations from each other to get rid of a variable.

I am going to get rid of y first.

2y-2x=3

-2y+5x=3

When you use elimination to add and subtract, you get the equation:

3x=6

Simplify for:

x=2

There are two ways to find y. The easier way is to plug x=2 back into one of the original equations and solve, or you can use elimination again. To use elimination to find y:

First we have to make it so that our x's will add or subtract to 0 in the two original equations by multiplying.

5 * (2y-2x=3) = 10y-10x=15

2 * (-2y+5x=3) = -4y+10x=15

Adding those two equations together will give us:

6y=30

Simplify:

y=5

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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