14. there were 200 tickets sold for a women's basketball game. tickets for students were 50 cents each
and for adults 75 cents each. the total amount of money collected was $132.50. how many of each type
of ticket was sold?

Number of students ticket sold = 70

Number of Adult ticket sold      =  130

Step-by-step explanation:

Given as ,

Total number of tickets sold = 200

Each student tickets cost = 50 cents = $0.5                Note : $ 1 = 100 cents

Each Adult tickets cost     = 75 cents  = $0.75

Total amount of money collected = $ 132.50

Now,

Let student = S       and Adult = A

So, S + A = 200                .... 1

And, 0.5S + 0.75 A = 132.50       ....2

Solve both equations

0.5 S + 0.5 A = 100

0.5 s + 0.75 A = 132.52

Again, (0.5 S + 0.75 A) - (0.5 S + 0.5 A ) = 32.50

             0.25 A = 32.50

         so , A = 130

Now put this A value in above eq ,  

Then, 0.5S + 0.5 (130) = 100

         0.5 S = 100 - 65 = 35

          So , S = = 70

Hence, Number of students ticket sold = 70

            Number of Adult ticket sold      =  130         Answer

there is no answer sorry!

step-by-step explanation:

i don't think there is enough