Which list includes the lower extreme, the lower quartile, the median, the upper quartile, and the upper extreme for the data set given?
14, 30, 35, 8, 29, 28, 31, 42, 20, 36, 32
{8, 24, 30, 33.5, 42}
{8, 20, 30, 36, 42}
{8, 20, 30, 35, 42}
{8, 24, 30, 36, 42}

(C) {8, 20, 30, 35, 42}

Step-by-step explanation:

The given data set is:

14, 30, 35, 8, 29, 28, 31, 42, 20, 36, 32

In order to find the median, first arrange the given data set in ascending order that is:

8, 14, 20, 28, 29, 30, 31, 32, 35, 36, 42

Now, the median of the given data set is:

(Median is the middle value of the given data set)

Also, the lower Quartile is:

8, 14, 20, 28, 29

Thus,

And, the upper quartile is:

31, 32, 35, 36, 42

Thus,

Now, the lower extreme value is 8 and the upper extreme value is 42.

Thus, the list that includes the lower extreme, the lower quartile, the median, the upper quartile, and the upper extreme for the data set given is

{8, 20, 30, 35, 42}.

Therefore, option (C) is correct that is {8, 20, 30, 35, 42}

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

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