Question 3.9 uses a binomial distribution to count the number of twinsout of 60 students. surprisingly, the question treats a set of twins asa person. i believe that it should not be. if there is a set of twins, x should be 2 not 1. similarly if there are 2 sets of twins, x should take on 4 not 2. assume that all twins goes to the same school, let x denote the number of twins out 60 students. the probability of a twin birth is approximately 1/90. find the pmf of x.

i can try and you the very best that i can.

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !