What is the equation in standard form of a line that passes through (1,24) and has a slope of -0.6? ?

5y+3x=123

Step-by-step explanation:

(x1,y1)=(1,24), m=-0.6

y-y1=m(x-x1)

y-24=-0.6(x-1)

y-24=-6/10(x-1)

10(y-24)=-6(x-1)

10y-240=-6x+6

10y+6x=6+240

10y+6x=246

divide by through by 2

5y+3x=123

the diameter is 16 cm. are you a teacher?

step-by-step explanation:

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0