How do i solve for x in the equation 5^x=3125? also in 5^x=1/125, 9^x=243, 4^x=1/32, and 3*2^x=96?

Remember
if x^m=x^n and x=x, m=n
also
x^-m=1/(x^m)
(x^m)^n=x^(mn)

try to match bases

5^x=3125
5^x=5^5
x=5

5^x=1/125
1/125=1/(5^3)=5^-3
5^x=5^-3
x=-3

9^x=234
3^(2x)=3^5
2x=5
x=2.5

4^x=1/32
1/32=1/(2^5)=2^-5
2^(2x)=2^-5
2x=-5
x=-2.5

3*2^x=96
first divide both sides by 3
2^x=32
2^x=2^5
x=5

5^x=3125
x=5

5^x=1/125
x=-3

9^x=234
x=2.5

4^x=1/32
x=-2.5

3*2^x=96
x=5

The answer would be choice b